Calculate Overall Heat Transfer Coefficient Calculator

Enter your engineering parameters below to compute verified physical and mathematical metrics.

Inside fluid convection coefficient in W/m²·K (e.g. Liquid Water = 1,000 W/m²·K).
Thermal conductivity of wall material in W/m·K (e.g. Steel = 50, Copper = 400).
Wall thickness in meters (e.g. 0.010 m = 10 mm).
Outside fluid convection coefficient in W/m²·K (e.g. Ambient Air = 25 W/m²·K).

Calculation Results

Primary Metric Output --
Metric Breakdown 1 --
Metric Breakdown 2 --
Metric Breakdown 3 --
Metric Breakdown 4 --
Metric Breakdown 5 --
Mathematical Standard --

Calculated using verified physical methodology: Overall Heat Transfer Coefficient: U = \1 / \frac{1{h_i} + \d / k + \1 / h_o}
Total Thermal Resistance: R_{total} = \1 / U = R_i + R_{wall} + R_o

*Note: Results represent standard engineering estimates. Validate with structural codes (AISC, Eurocode) or laboratory test measurements for mission-critical applications.

Quick Summary

The Overall Heat Transfer Coefficient Calculator evaluates the combined composite U-factor ($U = \1 / \frac{1{h_i} + \d / k + \1 / h_o}$) across inside fluid convection, solid wall conduction, and outside fluid convection.

Formula Explanation

Overall Heat Transfer Coefficient: U = \1 / \frac{1{h_i} + \d / k + \1 / h_o}
Total Thermal Resistance: R_{total} = \1 / U = R_i + R_{wall} + R_o

How It Works

The Overall Heat Transfer Coefficient Calculator sums individual thermal resistances in series: inside film resistance ($R_i = 1/h_i$), solid wall conductive resistance ($R_{wall} = d/k$), and outside film resistance ($R_o = 1/h_o$). Taking the reciprocal of total resistance ($R_{total}$) yields the overall U-factor ($U$).

Step-by-Step Worked Example

Practical Problem: Calculate the overall U-factor for a 10 mm steel vessel wall ($k = 50\text{ W/m}\cdot\text{K}$) separating hot water ($h_i = 1,000\text{ W/m}^2\cdot\text{K}$) from ambient air ($h_o = 25\text{ W/m}^2\cdot\text{K}$).

  1. Step 1: Identify Input Parameters: $h_i = 1,000\text{ W/m}^2\cdot\text{K}$, $k = 50\text{ W/m}\cdot\text{K}$, $d = 0.010\text{ m}$, $h_o = 25\text{ W/m}^2\cdot\text{K}$.
  2. Step 2: Calculate Individual Thermal Resistances: $R_i = \1 / 1000 = 0.0010\text{ m}^2\cdot\text{K/W}$, $R_{wall} = \0.010 / 50 = 0.0002\text{ m}^2\cdot\text{K/W}$, $R_o = \1 / 25 = 0.0400\text{ m}^2\cdot\text{K/W}$.
  3. Step 3: Sum Total Series Thermal Resistance: $R_{total} = 0.0010 + 0.0002 + 0.0400 = 0.0412\text{ m}^2\cdot\text{K/W}$.
  4. Step 4: Execute Reciprocal Division for U-Factor: $U = \1 / R_{total} = \1 / 0.0412 = 24.2718\text{ W/m}^2\cdot\text{K}$.
  5. Step 5: Convert and Interpret Imperial Metric Outputs: Overall U-Factor $U = 24.27\text{ W/m}^2\cdot\text{K}$. Imperial U-Factor: $24.2718 \times 0.176110 = 4.274\text{ BTU/hr}\cdot\text{ft}^2\cdot^\circ\text{F}$. Imperial R-Value: $R_{total,us} = \1 / 4.274 = 0.234\text{ hr}\cdot\text{ft}^2\cdot^\circ\text{F/BTU}$. Controlling resistance is the outside air convection film ($97.1\%$ of total thermal resistance).

Real-World Calculation Examples

Scenario 1: Water-to-Air Steel Vessel Wall

Parameters: $h_i = 1,000$, $k = 50$, $d = 0.010\text{ m}$, $h_o = 25$

Result: $U = 24.27\text{ W/m}^2\cdot\text{K}$ (4.27 BTU/hr·ft²·°F). Air film controls U-factor.

Scenario 2: Water-to-Water Shell-and-Tube Exchanger

Parameters: $h_i = 3,000$, $k = 400$ (copper), $d = 0.002\text{ m}$, $h_o = 2,500$

Result: $U = 1,353.16\text{ W/m}^2\cdot\text{K}$ (238.30 BTU/hr·ft²·°F). High-efficiency heat exchanger.

Scenario 3: Insulated Building Wall Assembly

Parameters: $h_i = 8.3$, $k = 0.04$ (insulation), $d = 0.100\text{ m}$, $h_o = 25$

Result: $U = 0.376\text{ W/m}^2\cdot\text{K}$ (0.066 BTU/hr·ft²·°F). Building wall thermal U-factor.

Scenario 4: Double-Glazed Glass Window Assembly

Parameters: $h_i = 8.3$, $k = 0.026$ (air gap), $d = 0.012\text{ m}$, $h_o = 25$

Result: $U = 1.608\text{ W/m}^2\cdot\text{K}$ (0.283 BTU/hr·ft²·°F). Double-pane window U-factor.

Key Benefits of Using This Calculator

Heat Exchanger & HVAC Design

Essential tool for sizing shell-and-tube, plate-and-frame, and HVAC hydronic heat exchangers.

Controlling Resistance Breakdown

Identifies which individual layer ($R_i$, $R_{wall}$, $R_o$) controls thermal performance.

SI & Imperial U-Factor & R-Value

Provides readouts in $\text{W/m}^2\cdot\text{K}$, $\text{BTU/hr}\cdot\text{ft}^2\cdot^\circ\text{F}$, SI R-value, and US R-value.

100% Free & Client-Side

Executes locally in your browser with zero latency or web server transmission.

Frequently Asked Questions (FAQ)

What is Overall Heat Transfer Coefficient (U-factor)?

The overall heat transfer coefficient (U) measures overall heat flow rate per unit area per unit temperature difference across composite convective and conductive layers.

What is the formula for overall U-factor across a flat wall?

U = 1 / (1/hi + sum(d_k / k_k) + 1/ho), where 1/hi is inside film resistance, d/k is wall conductive resistance, and 1/ho is outside film resistance.

How does U-factor relate to R-value?

U-factor is reciprocal to total thermal resistance: U = 1 / R_total and R_total = 1 / U.

What is meant by the controlling thermal resistance?

The controlling resistance is the largest individual thermal resistance in series (e.g. gas film h ~ 25 W/m²·K), which limits overall heat transfer regardless of how conductive the metal wall is.

How converts W/m²·K to BTU/hr·ft²·°F?

Multiply W/m²·K by 0.176110 to obtain BTU/hr·ft²·°F (e.g. 24.27 W/m²·K = 4.27 BTU/hr·ft²·°F).

How is fouling factor included in heat exchanger U-factor calculations?

Fouling resistances (Rf,i and Rf,o) are added in series: 1/U = 1/hi + Rf,i + d/k + Rf,o + 1/ho, accounting for scale and rust buildup.

What is the overall heat transfer coefficient for circular pipes?

For cylindrical pipes, Area varies with radius: 1/(U_o * A_o) = 1/(h_i * A_i) + ln(r_o/r_i)/(2 * pi * k * L) + 1/(h_o * A_o).

What typical U-values exist in building insulation codes?

Energy efficient walls: U ~ 0.20 to 0.35 W/m²·K (R-15 to R-25); Energy efficient windows: U ~ 1.2 to 1.8 W/m²·K.

Why does high wall conductivity k have minimal impact when fluid convection h is low?

Because wall resistance d/k is negligible compared to fluid film resistance 1/h (e.g. 0.0002 vs 0.0400 m²·K/W), making fluid boundary layers dominate total resistance.

How is total heat transfer rate calculated from U-factor?

Q = U * A * LMTD, where A is heat transfer area and LMTD is Logarithmic Mean Temperature Difference across the heat exchanger.