n! Factorial Solver

Enter a non-negative integer n (0 ≤ n ≤ 1000).

Enter integer n from 0 up to 1000.

Factorial Output

Calculated Factorial n! 6! = 720
Total Digit Length 3 digits long
Trailing Zero Count 1 trailing zero
Stirling's Approximation 710.08 (Asymptotic estimate)
Expanded Expression 6 × 5 × 4 × 3 × 2 × 1

Quick Summary

Our factorial calculator n exclamation steps tool evaluates the product of all positive integers less than or equal to $n$ ($n! = n \times (n-1) \dots \times 1$). It provides exact BigInt precision, trailing zeros count, total digit length, and Stirling's asymptotic approximation.

How It Works: Factorial Multiplication & Properties

The factorial operation grows extremely rapidly (super-exponentially):
1. **Definition ($n!$):** $n! = n \times (n-1) \times (n-2) \times \dots \times 2 \times 1$.
2. **Zero Factorial Convention ($0!$):** By mathematical definition, $0! = 1$ (representing the single empty set arrangement).
3. **Legendre's Formula (Trailing Zeros):** Count factors of 5 in $n! \implies Z(n) = \sum_{k=1}^\infty \lfloor \n / 5^k \rfloor$.
4. **Stirling's Approximation:** For large $n$, $n! \approx \sqrt{2\pi n} \left(\n / e\right)^n$.

Formula Explanation

Your factorial calculations use product definitions and Stirling's equation:

n! = \prod_{k=1}^n k = n \times (n-1) \times \dots \times 1, \quad 0! = 1
n! \approx \sqrt{2\pi n} \left(\n / e\right)^n, \quad \text{Trailing Zeros} = \sum_{k=1}^{\infty} \left\lfloor \n / 5^k \right\rfloor

Step-by-Step Worked Example

Here is a detailed 5-step breakdown for calculating 6!:

  1. Step 1 (Write Expression): $6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1$.
  2. Step 2 (Multiply First Pair): $6 \times 5 = \mathbf{30}$.
  3. Step 3 (Multiply Next Factors): $30 \times 4 = \mathbf{120}$.
  4. Step 4 (Continue Product): $120 \times 3 = \mathbf{360}$.
  5. Step 5 (Final Multiplication): $360 \times 2 \times 1 = \mathbf{720}$, delivering **6! = 720**!

Calculation Examples: Real-World Scenario Comparison

Compare factorial values, digit lengths, trailing zero counts, and Stirling estimates:

Integer Input (n) Calculated Factorial n! Digit Count Trailing Zeros Stirling's Estimate
0! 1 1 digit 0 zeros 1.00
6! 720 3 digits 1 zero 710.08
10! 3,628,800 7 digits 2 zeros 3,598,695.62
25! 15,511,210,043,330,985,984,000,000 26 digits 6 zeros 1.5459e+25

Benefits of Using the Factorial Calculator

Utilizing this calculator provides essential combinatorics, Taylor series, and probability advantages:

  • BigInt Arbitrary Precision: Calculates exact factorials up to 1000! without truncation or scientific notation loss.
  • Trailing Zeros Solver: Computes the exact count of trailing zeros using Legendre's formula.
  • Combinatorics & Probability Core: Essential building block for permutations ($nPr$), combinations ($nCr$), and binomial expansions.
  • Taylor Series & Calculus: Computes denominators for sine, cosine, and exponential $e^x$ series expansions.

Frequently Asked Questions (FAQ)

What is a factorial in math?

A factorial (denoted by n!) is the product of all positive integers less than or equal to n.

Why is 0! equal to 1?

0! = 1 by definition because there is exactly 1 way to arrange 0 items (an empty set). It also maintains algebraic consistency for n! = n × (n - 1)!.

Can negative numbers have factorials?

Standard factorials are defined only for non-negative integers. Negative integers do not have valid factorials (Gamma function has poles at negative integers).

What is Stirling's approximation?

Stirling's approximation (n! ≈ √(2πn) × (n/e)^n) estimates large factorials without performing all individual multiplications.

How do you find the number of trailing zeros in n!?

Count factors of 5 in n! using Legendre's formula: ⌊n/5⌋ + ⌊n/25⌋ + ⌊n/125⌋ + ...

What is 5!?

5! = 5 × 4 × 3 × 2 × 1 = 120.

What is 10!?

10! = 3,628,800.

How fast does n! grow?

Factorial growth (O(n!)) is faster than exponential growth (O(2^n) or O(e^n)), making factorials grow extremely huge even for small n (e.g. 52! has 68 digits).

What is the Gamma function?

The Gamma function Γ(z) extends factorials to real and complex numbers, where Γ(n) = (n - 1)!.

What are subfactorials (!n)?

Subfactorials (!n) count derangements—permutations of n elements where no element appears in its original position.