Calculate Pipe Constriction Velocity (A1 · v_1 = A2 · v_2)

Enter your physical parameters below to compute verified fluid velocity metrics.

Entry cross-sectional area in m^2 (e.g. 0.05 m²).
Entry velocity in m/s (e.g. 2.0 m/s).
Exit cross-sectional area in m^2 (e.g. 0.01 m²).

Calculation Results

Primary Metric Output --
Metric Breakdown 1 --
Metric Breakdown 2 --
Metric Breakdown 3 --
Metric Breakdown 4 --
Metric Breakdown 5 --
Mathematical Standard --

Calculated using verified physical methodology: Continuity Equation: A1 \cdot v_1 = A2 \cdot v_2
Exit Velocity: v_2 = v_1 \left(\A1 / A2\right)

*Note: Results represent mass flow conservation in incompressible fluids.

Quick Summary

The Continuity Equation Calculator evaluates fluid conservation of mass ($A1 \cdot v_1 = A2 \cdot v_2$) in pipe constrictions and nozzles, computing exit velocity ($v_2 = v_1 \A1 / A2$) in m/s, km/h, ft/s, and velocity speedup ratios.

Formula Explanation

Continuity Equation: A1 \cdot v_1 = A2 \cdot v_2
Exit Velocity: v_2 = v_1 \left(\A1 / A2\right)

How It Works

The Continuity Equation Calculator multiplies entry pipe area ($A1$) by entry fluid velocity ($v_1$) to find conserved flow rate ($Q$). It divides flow rate ($Q$) by exit area ($A2$) to output exit velocity ($v_2$), speedup ratio ($A1 / A2$), and flow rate in L/min.

Step-by-Step Worked Example

Practical Problem: Water enters a pipe reducer nozzle with area $A1 = 0.05\text{ m}^2$ at velocity $v_1 = 2.0\text{ m/s}$. The nozzle area constricts to $A2 = 0.01\text{ m}^2$. Calculate exit fluid velocity $v_2$.

  1. Step 1: Identify Input Parameters: $A1 = 0.05\text{ m}^2$, $v_1 = 2.0\text{ m/s}$, $A2 = 0.01\text{ m}^2$.
  2. Step 2: Calculate Conserved Flow Rate ($Q = A1 \cdot v_1$): $Q = 0.05 \times 2.0 = 0.100\text{ m}^3/\text{s} = 6,000.0\text{ L/min}$.
  3. Step 3: Calculate Area Amplification Ratio ($A1 / A2$): $\text{Ratio} = \0.05 / 0.01 = 5.00\text{ (5x area constriction)}$.
  4. Step 4: Apply the Continuity Equation for Exit Velocity ($v_2$): $v_2 = v_1 \times 5.00 = 2.0\text{ m/s} \times 5.00 = 10.00\text{ m/s}$.
  5. Step 5: Format Final Velocity Metrics: Exit Velocity $v_2 = 10.00\text{ m/s} = 36.00\text{ km/h} = 32.81\text{ ft/s}$. Conserved Flow Rate = $6,000.0\text{ L/min}$. Speedup Multiplier = $5.0x$.

Real-World Calculation Examples

Scenario 1: Industrial Pipe Reducer Nozzle

Parameters: $A1 = 0.05\text{ m}^2$, $v_1 = 2.0\text{ m/s}$, $A2 = 0.01\text{ m}^2$

Result: $v_2 = 10.00\text{ m/s}$ (36.0 km/h, 5.0x speedup). Pipe constriction velocity.

Scenario 2: Garden Hose Finger Pinch Squeeze

Parameters: $A1 = 3.14\text{ cm}^2$, $v_1 = 1.5\text{ m/s}$, $A2 = 0.785\text{ cm}^2$ (75% pinch)

Result: $v_2 = 6.00\text{ m/s}$ (21.6 km/h, 4.0x speedup). Hose nozzle jet spray.

Scenario 3: Fire Engine Hose Taper Nozzle

Parameters: $A1 = 50\text{ cm}^2$, $v_1 = 3.0\text{ m/s}$, $A2 = 5\text{ cm}^2$ (90% reduction)

Result: $v_2 = 30.00\text{ m/s}$ (108.0 km/h, 10.0x speedup). High-speed fire jet spray.

Scenario 4: River Channel Narrowing Canyon Stream

Parameters: $A1 = 100\text{ m}^2$, $v_1 = 1.0\text{ m/s}$, $A2 = 25\text{ m}^2$

Result: $v_2 = 4.00\text{ m/s}$ (14.4 km/h, 4.0x speedup). River rapid canyon acceleration.

Key Benefits of Using This Calculator

Conservation of Mass Verification

Verifies incompressible fluid mass flow rate conservation across varying cross-sections ($A1 v_1 = A2 v_2$).

Nozzle & Reducer Pipe Design

Sizes nozzle tip diameters and pipe reducer fittings for fire hoses, sprayers, and jet engines.

Multi-Unit Readouts

Outputs velocity in m/s, km/h, and Imperial ft/s.

100% Free & Client-Side

Executes locally in your browser with zero latency or web server transmission.

Frequently Asked Questions (FAQ)

What is the Continuity Equation in fluid dynamics?

The Continuity Equation expresses the Law of Conservation of Mass for fluid flow: mass entering a pipe per unit time must equal mass exiting (rho1 * A1 * v1 = rho2 * A2 * v2).

What is the Continuity Equation formula for incompressible fluids?

For incompressible fluids (constant density rho), area and velocity product is constant: A1 * v1 = A2 * v2 (or Q1 = Q2).

Why does water speed up when squeezing a hose tip?

Pinch-squeezing the tip reduces exit area A2; since total flow rate Q = A * v is constant, decreasing area A forces fluid velocity v to increase dramatically.

How does pipe diameter change affect fluid velocity?

Since area A = pi * (d/2)², velocity v is inversely proportional to diameter squared (v2 / v1 = (d1 / d2)²); halving pipe diameter quadruples fluid velocity.

Does the Continuity Equation apply to gases?

For compressible gases at high speeds, density changes must be included: rho1 * A1 * v1 = rho2 * A2 * v2.

How relates Continuity Equation to Bernoulli's Equation?

The Continuity Equation determines velocity change v2 from area change A2; Bernoulli's Equation then uses this new velocity v2 to calculate static pressure P2.

What is volumetric flow rate Q?

Q = A1 * v1 = A2 * v2 (constant volume discharge in m³/s or L/min).

What is 1D steady-state flow assumption?

Assumes uniform average velocity across pipe cross-sections and constant mass flow rate over time.

How converts m/s to km/h?

Multiply m/s by 3.6 to obtain km/h (e.g. 10 m/s = 36 km/h).

How converts m/s to ft/s?

Multiply m/s by 3.28084 to obtain feet per second (ft/s) (e.g. 10 m/s = 32.81 ft/s).