Calculate Unordered Combinations C(n, r)

Enter total available items (n) and number of chosen items (r).

Total items $n$ (e.g. 5).
Chosen items $r$ ($0 \le r \le n$).

Calculation Results

Primary Metric Output --
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Metric Breakdown 5--
Mathematical Standard--

Calculated using combination binomial coefficient equations: C(n, r) = \binom{n}{r} = \frac{n!}{r! (n - r)!}

*Note: Combinations count unordered selections where sequence/order does not matter (e.g. ABC = CBA).

Quick Summary

The Combination Calculator evaluates unordered selections $C(n, r) = \frac{n!}{r!(n - r)!}$, combinations with repetition ($\binom{n+r-1}{r}$), and Pascal's triangle coefficients.

Formula Explanation

C(n, r) = \binom{n}{r} = \frac{n!}{r! (n - r)!}
\text{Combinations with Repetition} = \binom{n + r - 1}{r}

How It Works

A combination is a selection of items from a set where order does not matter. The Combination Calculator divides permutation count $P(n, r)$ by $r!$ to eliminate duplicate orderings.

Step-by-Step Worked Example

Practical Problem: Calculate the number of combinations when choosing $r = 3$ committee members from $n = 5$ candidates.

  1. Step 1: Calculate $n! = 5!$: $5! = \mathbf{120}$.
  2. Step 2: Calculate $r! = 3!$: $3! = \mathbf{6}$.
  3. Step 3: Calculate $(n - r)! = 2!$: $2! = \mathbf{2}$.
  4. Step 4: Divide $n!$ by $(r! \times (n-r)!)$: $C(5, 3) = 120 / (6 \times 2) = 120 / 12 = \mathbf{10\text{ combinations}}$.
  5. Step 5: Interpretation: There are 10 unique 3-member committees that can be formed from 5 candidates.

Real-World Calculation Examples

Scenario 1: 3 Items from 5 (C(5, 3))

Parameters: n = 5, r = 3
Result: C(5, 3) = 10 combinations (Order irrelevant).

Scenario 2: Lottery Ticket Ball Selection (6 from 49)

Parameters: n = 49, r = 6
Result: C(49, 6) = 13,983,816 combinations (1 in 14M odds).

Scenario 3: Poker Hands (5 cards from 52)

Parameters: n = 52, r = 5
Result: C(52, 5) = 2,598,960 possible hands.

Scenario 4: Ice Cream Scoops with Repetition (3 scoops, 5 flavors)

Parameters: n = 5, r = 3 with repetition
Result: C(5+3-1, 3) = C(7, 3) = 35 combinations.

Key Benefits of Using This Calculator

Unordered Combinations $C(n, r)$

Computes exact unordered subset selections where item order is irrelevant.

Pascal's Triangle Coefficient

Displays binomial expansion coefficients $(a+b)^n$.

Combinations with Repetition

Outputs combinations with replacement $\binom{n+r-1}{r}$ (stars and bars theorem).

100% Free & Client-Side

Executes locally in your browser with zero latency or web server transmission.

Frequently Asked Questions (FAQ)

What is a combination?

A combination is a selection of items from a collection where the order of selection does not matter ($C(n, r) = \frac{n!}{r!(n - r)!}$).

What is symmetry property of combinations?

$C(n, r) = C(n, n - r)$ (e.g. choosing 3 items to keep is identical to choosing 2 items to leave behind out of 5).

How do I calculate combinations in Excel?

Use formula =COMBIN(n, r) for no repetition or =COMBINA(n, r) for repetition allowed.

What is Pascal's Identity?

Pascal's Identity states $\binom{n}{r} = \binom{n-1}{r-1} + \binom{n-1}{r}$.

What is sum of a row in Pascal's Triangle?

The sum of row $n$ in Pascal's Triangle is $\sum_{r=0}^{n} \binom{n}{r} = 2^n$.

What is Binomial Theorem?

$(x + y)^n = \sum_{k=0}^{n} \binom{n}{k} x^{n-k} y^k$.

What is $C(n, 0)$ and $C(n, n)$ equal to?

$C(n, 0) = 1$ and $C(n, n) = 1$.

What is Stars and Bars theorem?

Stars and Bars theorem calculates combinations with repetition: $\binom{n + r - 1}{r}$.

Why is lottery probability calculated using combinations?

Because lottery numbers can be drawn in any order, combinations $C(N, r)$ determine winning ticket probabilities.

What is Vandermonde's Identity?

$\binom{m + n}{r} = \sum_{k=0}^{r} \binom{m}{k} \binom{n}{r - k}$.