Calculate Conditional Probability P(A|B)

Enter joint probability P(A ∩ B) and condition probability P(B).

Both A and B occur $P(A \cap B)$ (e.g. 0.15).
Given condition event B $P(B)$ (e.g. 0.30).
Prior unconditional $P(A)$ (e.g. 0.40).

Calculation Results

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Calculated using conditional probability definitions: P(A|B) = \frac{P(A \cap B)}{P(B)}

*Note: Conditional probability P(A|B) measures the probability of event A given that event B has occurred.

Quick Summary

The Conditional Probability Calculator evaluates conditional probability $P(A|B) = \frac{P(A \cap B)}{P(B)}$ and checks whether events A and B are independent.

Formula Explanation

P(A|B) = \frac{P(A \cap B)}{P(B)} \quad \text{where } P(B) > 0
\text{Independence Criterion: } P(A|B) = P(A)

How It Works

Conditional probability calculates the updated probability of event A after knowing event B has occurred. The Conditional Probability Calculator divides joint probability $P(A \cap B)$ by condition probability $P(B)$, verifying statistical independence.

Step-by-Step Worked Example

Practical Problem: In a student group, 30% take Spanish ($P(B) = 0.30$) and 15% take both Spanish and French ($P(A \cap B) = 0.15$). Calculate probability a student takes French given they take Spanish ($P(A|B)$).

  1. Step 1: Identify joint probability $P(A \cap B)$: $P(A \cap B) = \mathbf{0.15}$.
  2. Step 2: Identify condition probability $P(B)$: $P(B) = \mathbf{0.30}$.
  3. Step 3: Divide joint probability by condition probability: $P(A|B) = 0.15 / 0.30 = \mathbf{0.5000\text{ (50.00\%)}}.$
  4. Step 4: Test for Independence: If unconditional $P(A) = 0.40$, $P(A|B) = 0.50 \neq 0.40$.
  5. Step 5: Interpretation: Taking Spanish increases French enrollment probability from 40% to 50% (dependent events).

Real-World Calculation Examples

Scenario 1: Language Enrollment (P(A∩B)=0.15, P(B)=0.30)

Parameters: P(A∩B) = 0.15, P(B) = 0.30
Result: P(A|B) = 0.5000 (50.00% conditional probability).

Scenario 2: Medical Diagnostic Test Accuracy

Parameters: True positive P(T∩D) = 0.045, Disease P(D) = 0.05
Result: P(T|D) = 0.9000 (90% Sensitivity).

Scenario 3: E-Commerce Purchase Given Cart Add

Parameters: P(Purchase∩Cart) = 0.20, P(Cart) = 0.50
Result: P(Purchase|Cart) = 0.4000.

Scenario 4: Card Deck Probability (Ace given Red)

Parameters: P(Red Ace) = 2/52, P(Red Card) = 26/52
Result: P(Ace|Red) = 2/26 = 1/13.

Key Benefits of Using This Calculator

Instant Conditional Updating

Updates event probabilities based on known condition evidence.

Statistical Independence Testing

Compares $P(A|B)$ with $P(A)$ to verify independent vs dependent events.

Joint & Marginal Probability Sync

Integrates joint $P(A \cap B)$ and marginal $P(B)$ inputs.

100% Free & Client-Side

Executes locally in your browser with zero latency or web server transmission.

Frequently Asked Questions (FAQ)

What is conditional probability $P(A|B)$?

Conditional probability $P(A|B)$ is the probability that event A occurs given that event B has already occurred.

What is Multiplication Rule of Probability?

$P(A \cap B) = P(B) \cdot P(A|B) = P(A) \cdot P(B|A)$.

How do I test if two events A and B are independent?

Events A and B are independent if $P(A|B) = P(A)$ or $P(A \cap B) = P(A) \cdot P(B)$.

What is difference between $P(A|B)$ and $P(B|A)$?

$P(A|B)$ conditions on B; $P(B|A)$ conditions on A. In general, $P(A|B) \neq P(B|A)$ (Confusion of the Inverse fallacy!).

Can conditional probability be calculated if $P(B) = 0$?

No — division by zero is undefined; conditional probability requires $P(B) > 0$.

How does Bayes Theorem relate to conditional probability?

Bayes Theorem reverses conditional probability: $P(A|B) = \frac{P(B|A) P(A)}{P(B)}$.

What is Law of Total Probability?

$P(B) = \sum P(B|A_i) P(A_i)$ across a partition of sample space.

How do I calculate conditional probability in Excel?

Use division formula =P_A_and_B / P_B.

What is Monty Hall Problem?

The Monty Hall problem is a famous conditional probability puzzle where switching doors doubles your win probability from 1/3 to 2/3.

What is Simpson's Paradox?

Simpson's paradox occurs when a conditional probability trend in several groups reverses when groups are combined.